HP 48gII Graphing Calculator Manual do Utilizador descarregar pdf (Página 503)

OBJ ƒ ƒ Isolates right-hand side of last expression

ILAP Obtains the inverse Laplace transform

The result is ‘y1*SIN(X-1)+y0*COS(X-1)-(COS(X-3)-1)*Heaviside(X-3)’.

Thus, we write as the solution: y(t) = y

sin t + H(t-3)⋅(1+sin(t-3)).

Check what the solution to the ODE would be if you use the function LDEC:

‘H(X-3)’ `[ENTER] ‘X^2+1’ ` LDEC

The result is:

Please notice that the variable X in this expression actually represents the

variable t in the original ODE, and that the variable ttt in this expression is a

dummy variable. Thus, the translation of the solution in paper may be written

– Plot the solution to Example 3 using the same values of y

used in the plot of Example 1, above. We now plot the function

y(t) = 0.5 cos t –0.25 sin t + (1+sin(t-3))⋅H(t-3).

In the range 0 < t < 20, and changing the vertical range to (-1,3), the graph

should look like this:

.)3(sinsincos)(

⋅⋅−⋅+⋅+⋅= dueuHttCtCoty

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HP 48gII Graphing Calculator Manual do Utilizador Página 503